Largest number in K swaps
Problem Statement - link #
Given a number K
and string str of digits denoting a positive integer, build the largest number possible by performing swap operations on the digits of str at most K
times.
Your Task:
You don’t have to read input or print anything. Your task is to complete the function findMaximumNum()
which takes the string and an integer as input and returns a string containing the largest number formed by perfoming the swap operation at most k
times..
Expected Time Complexity: O(n!/(n-k)!)
, where n
= length of input string
Expected Auxiliary Space: O(n)
Examples #
Example 1:
Input:
K = 3
str = "3435335"
Output:
5543333
Explanation:
Three swaps can make the input
3435335 to 5543333, swapping 3
with 5, 4 with 5 and finally 3 with 4
Example 2:
Input:
K = 4
str = "1234567"
Output:
7654321
Explanation:
Three swaps can make the
input 1234567 to 7654321, swapping 1
with 7, 2 with 6 and finally 3 with 5
Constraints #
1 ≤ |str| ≤ 30
1 ≤ K ≤ 10
Solutions #
class Solution
{
public:
void solve(int i,string str,string &res,int n,int k){
res = max(res,str);
if(i==n || k==0) return;
char mc = str[i];
for(int j=i+1;j<n;j++) mc=max(mc,str[j]);
if(mc > str[i]) {
for(int j=i+1; j<n; j++){
if(str[j]==mc) {
swap(str[i],str[j]);
solve(i+1,str,res,n,k-1);
swap(str[i],str[j]);
}
}
}else solve(i+1,str,res,n,k);
}
//Function to find the largest number after k swaps.
string findMaximumNum(string str, int k) {
// code here.
int n = str.size();
string res = str;
solve(0,str,res,n,k);
return res;
}
};