Add Digits
Problem Statement - link #
Given an integer num
, repeatedly add all its digits until the result has only one digit, and return it.
Examples #
Example 1:
Input: num = 38
Output: 2
Explanation: The process is
38 --> 3 + 8 --> 11
11 --> 1 + 1 --> 2
Since 2 has only one digit, return it.
Example 2:
Input: num = 0
Output: 0
Constraints #
0 <= num <= 2^31 - 1
Solutions #
class Solution {
public:
int addDigits(int num) {
return num == 0 ? 0 : 1 + (num - 1) % 9;
}
};
class Solution {
public:
int addDigits(int num) {
int digitalRoot = 0;
while (num > 0) {
digitalRoot += num % 10;
num = num / 10;
if (num == 0 && digitalRoot > 9) {
num = digitalRoot;
digitalRoot = 0;
}
}
return digitalRoot;
}
};