4Sum
Problem Statement - link #
Given an array nums
of n
integers, return an array of all the unique quadruplets [nums[a], nums[b], nums[c], nums[d]]
such that:
0 <= a, b, c, d < n
a,
b,
c,
andd
are distinct.nums[a] + nums[b] + nums[c] + nums[d] == target
You may return the answer in any order.
Examples #
Example 1:
Input: nums = [1,0,-1,0,-2,2], target = 0
Output: [[-2,-1,1,2],[-2,0,0,2],[-1,0,0,1]]
Example 2:
Input: nums = [2,2,2,2,2], target = 8
Output: [[2,2,2,2]]
Constraints #
1 <= nums.length <= 200
-10^9 <= nums[i] <= 10^9
-10^9 <= target <= 10^9
Solutions #
class Solution {
public:
vector<vector<int>> fourSum(vector<int>& nums, int target) {
sort(nums.begin(), nums.end());
vector<vector<int>> res;
int n = nums.size();
for(int i=0; i<n; i++){
for(int j=i+1; j<n; j++){
int l = j+1, r = n-1;
int t = target - nums[i] - nums[j];
while(l<r){
int s = nums[l] + nums[r];
if(s<t) l++;
else if(s>t) r--;
else{
vector<int> v = {nums[i],nums[j],nums[l],nums[r]};
res.push_back(v);
while(l<r and nums[l]==v[2]) l++;
while(l<r and nums[r]==v[3]) r--;
}
}
while(j+1<n and nums[j]==nums[j+1]) j++;
}
while(i+1<n and nums[i]==nums[i+1]) i++;
}
return res;
}
};