Two Sum
Problem Statement - link #
Given an array of integers nums
and an integer target
, return indices of the two numbers such that they add up to target
.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
You can return the answer in any order.
Examples #
Example 1:
Input: nums = [2,7,11,15], target = 9
Output: [0,1]
Output: Because nums[0] + nums[1] == 9, we return [0, 1].
Example 2:
Input: nums = [3,2,4], target = 6
Output: [1,2]
Example 3:
Input: nums = [3,3], target = 6
Output: [0,1]
Constraints #
2 <= nums.length <= 10^4
-10^9 <= nums[i] <= 10^9
-10^9 <= target <= 10^9
- Only one valid answer exists
Solutions #
class Solution {
public:
vector<int> twoSum(vector<int>& nums, int target) {
unordered_map<int,int> mnk;
int i = 0;
for(;i<nums.size();i++){
if(mnk.find(target-nums[i]) != mnk.end())
return {i,mnk[target-nums[i]]};
mnk[nums[i]] = i;
}
return {};
}
};