Patients With a Condition
Problem Statement - link #
SQL Schema
Create table If Not Exists Patients (patient_id int, patient_name varchar(30), conditions varchar(100))
Truncate table Patients
insert into Patients (patient_id, patient_name, conditions) values ('1', 'Daniel', 'YFEV COUGH')
insert into Patients (patient_id, patient_name, conditions) values ('2', 'Alice', '')
insert into Patients (patient_id, patient_name, conditions) values ('3', 'Bob', 'DIAB100 MYOP')
insert into Patients (patient_id, patient_name, conditions) values ('4', 'George', 'ACNE DIAB100')
insert into Patients (patient_id, patient_name, conditions) values ('5', 'Alain', 'DIAB201')
Table: Patients
+--------------+---------+
| Column Name | Type |
+--------------+---------+
| patient_id | int |
| patient_name | varchar |
| conditions | varchar |
+--------------+---------+
patient_id is the primary key for this table.
'conditions' contains 0 or more code separated by spaces.
This table contains information of the patients in the hospital.
Your Task:
Write an SQL query to report the patient_id, patient_name all conditions of patients who have Type I Diabetes. Type I Diabetes always starts with DIAB1 prefix
Return the result table in any order.
The query result format is in the following example
Example #
Input:
Patients table:
+------------+--------------+--------------+
| patient_id | patient_name | conditions |
+------------+--------------+--------------+
| 1 | Daniel | YFEV COUGH |
| 2 | Alice | |
| 3 | Bob | DIAB100 MYOP |
| 4 | George | ACNE DIAB100 |
| 5 | Alain | DIAB201 |
+------------+--------------+--------------+
Output:
+------------+--------------+--------------+
| patient_id | patient_name | conditions |
+------------+--------------+--------------+
| 3 | Bob | DIAB100 MYOP |
| 4 | George | ACNE DIAB100 |
+------------+--------------+--------------+
Explanation: Bob and George both have a condition that starts with DIAB1.
Solutions #
-- Write your T-SQL query statement below
select patient_id, patient_name, conditions
from patients
where conditions like 'DIAB1%'
or conditions like '% DIAB1%'
;