Non Repeating Character
Problem Statement - link #
Given a string S
consisting of lowercase Latin Letters. Return the first non-repeating character in S
. If there is no non-repeating character, return ‘$
’.
Your Task: You only need to complete the function nonrepeatingCharacter()
that takes string S
as a parameter and returns the character. If there is no non-repeating character then return ‘$
’ .
Expected Time Complexity: O(N)
Expected Auxiliary Space: O(Number of distinct characters)
Examples #
Example 1:
Input:
S = hello
Output: h
Explanation: In the given string, the
first character which is non-repeating
is h, as it appears first and there is
no other 'h' in the string.
Example 2:
Input:
S = zxvczbtxyzvy
Output: c
Explanation: In the given string, 'c' is
the character which is non-repeating.
Constraints #
1 <=|S| ≤ 1000
Solutions #
class Solution{
public:
//Function to find the first non-repeating character in a string.
char nonrepeatingCharacter(string s)
{
//Your code here
unordered_map<char, int> um;
for(char c: s) um[c]++;
for(int i=0; i<s.size(); i++)
if(um[s[i]]==1) return s[i];
return '$';
}
};