Hand of Straights
Problem Statement - link #
Alice has some number of cards and she wants to rearrange the cards into groups so that each group is of size groupSize, and consists of groupSize
consecutive cards.
Given an integer array hand where hand[i]
is the value written on the ith
card and an integer groupSize
, return true
if she can rearrange the cards, or false
otherwise.
Examples #
Example 1:
Input: hand = [1,2,3,6,2,3,4,7,8], groupSize = 3
Output: true
Explanation: Alice's hand can be rearranged as [1,2,3],[2,3,4],[6,7,8]
Example 2:
Input: hand = [1,2,3,4,5], groupSize = 4
Output: false
Explanation: Alice's hand can not be rearranged into groups of 4.
Constraints #
1 <= hand.length <= 10^4
0 <= hand[i] <= 10^9
1 <= groupSize <= hand.length
Note: This question is the same as 1296: https://leetcode.com/problems/divide-array-in-sets-of-k-consecutive-numbers/
Solutions #
class Solution {
public:
bool isNStraightHand(vector<int>& hand, int groupSize) {
if(hand.size()%groupSize) return false;
map<int, int> mp;
sort(hand.begin(), hand.end());
for(int i: hand)
mp[i]++;
while(mp.size()){
auto m = mp.begin();
for(int i=1; i<groupSize; i++){
int _m = m->first+i;
if(mp.find(_m)==mp.end()) return false;
int f = m->second;
int _f = mp[_m];
if(_f < f) return false;
if(_f == f) mp.erase(_m);
else mp[_m] -= f;
}
mp.erase(m->first);
}
return mp.size()==0;
}
};