Merge Triplets to Form Target Triplet
Problem Statement - link #
A triplet is an array of three integers. You are given a 2D integer array triplets
, where triplets[i] = [ai, bi, ci]
describes the ith
triplet. You are also given an integer array target = [x, y, z]
that describes the triplet you want to obtain.
To obtain target
, you may apply the following operation on triplets
any number of times (possibly zero):
- Choose two indices (0-indexed)
i
andj (i != j)
and updatetriplets[j]
to become[max(ai, aj), max(bi, bj), max(ci, cj)]
.- For example, if
triplets[i] = [2, 5, 3]
andtriplets[j] = [1, 7, 5]
,triplets[j]
will be updated to[max(2, 1), max(5, 7), max(3, 5)] = [2, 7, 5]
.
- For example, if
Return true
if it is possible to obtain the target
triplet [x, y, z]
as an element of triplets
, or false
otherwise.
Examples #
Example 1:
Input: triplets = [[2,5,3],[1,8,4],[1,7,5]], target = [2,7,5]
Output: true
Explanation: Perform the following operations:
- Choose the first and last triplets [[2,5,3],[1,8,4],[1,7,5]]. Update the last triplet to be [max(2,1), max(5,7), max(3,5)] = [2,7,5]. triplets = [[2,5,3],[1,8,4],[2,7,5]]
The target triplet [2,7,5] is now an element of triplets.
Example 2:
Input: triplets = [[1,3,4],[2,5,8]], target = [2,5,8]
Output: true
Explanation: The target triplet [2,5,8] is already an element of triplets.
Example 3:
Input: triplets = [[2,5,3],[2,3,4],[1,2,5],[5,2,3]], target = [5,5,5]
Output: true
Explanation: Perform the following operations:
- Choose the first and third triplets [[2,5,3],[2,3,4],[1,2,5],[5,2,3]]. Update the third triplet to be [max(2,1), max(5,2), max(3,5)] = [2,5,5]. triplets = [[2,5,3],[2,3,4],[2,5,5],[5,2,3]].
- Choose the third and fourth triplets [[2,5,3],[2,3,4],[2,5,5],[5,2,3]]. Update the fourth triplet to be [max(2,5), max(5,2), max(5,3)] = [5,5,5]. triplets = [[2,5,3],[2,3,4],[2,5,5],[5,5,5]].
The target triplet [5,5,5] is now an element of triplets.
Example 4:
Input: triplets = [[3,4,5],[4,5,6]], target = [3,2,5]
Output: false
Explanation: It is impossible to have [3,2,5] as an element because there is no 2 in any of the triplets.
Constraints #
n == nums.length
2 <= n <= 1000
1 <= nums[i] <= 109
Solution #
class Solution {
public:
bool mergeTriplets(vector<vector<int>>& triplets, vector<int>& target) {
vector<bool> flag = {false,false,false};
for(int i = 0; i < triplets.size() ; i++){
if( triplets[i][0] == target[0] && triplets[i][1] <= target[1] && triplets[i][2] <= target[2] ){
flag[0] = true;
}
if( triplets[i][0] <= target[0] && triplets[i][1] == target[1] && triplets[i][2] <= target[2] ){
flag[1] = true;
}
if( triplets[i][0] <= target[0] && triplets[i][1] <= target[1] && triplets[i][2] == target[2] ){
flag[2] = true;
}
}
return flag[0] && flag[1] && flag[2] ;
}
};